C Program to find Minimum Cost With Example
We can explain C Program for Minimum Cost With Example with simple Examples.
The cost of operation of a unit consists of two components C1 and C2 which can be expressed as functions of parameter p as follows:
C1 = 30 – 8p
C2 = 10 + p2
The parameter p ranges from 0 to 10. Determine the value of p with an accuracy of + 0.1 where the cost of operation would be minimum.
C Program for Minimum Cost With Example
Problem Analysis:
Total cost = C1 + C2 = 40 – 8p + p2
The cost is 40 when p = 0, and 33 when p = 1 and 60 when p = 10. The cost, therefore, decreases first and then increases. The program in below evaluates the cost at successive intervals of p (in steps of 0.1) and stops when the cost begins to increase. The C program employs break and continue statements to exit the loop.
main()
{
float p, cost, p1, cost1;
for (p = 0; p <= 10; p = p + 0.1)
{
cost = 40 - 8 * p + p * p;
if(p == 0)
{
cost1 = cost;
continue;
}
if (cost >= cost1)
break;
cost1 = cost;
p1 = p;
}
p = (p + p1)/2.0;
cost = 40 - 8 * p + p * p;
printf("\nMINIMUM COST = %.2f AT p = %.1f\n",
cost, p);
}Output
MINIMUM COST = 24.00 AT p = 4.0
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